如何捕获 ls 或 find 命令的输出以将所有文件名存储在数组中? [英] How do I capture the output from the ls or find command to store all file names in an array?

问题描述

需要一次处理一个当前目录中的文件.我正在寻找一种方法来获取 ls 或 find 的输出并将结果值存储为数组的元素.这样我可以根据需要操作数组元素.

Need to process files in current directory one at a time. I am looking for a way to take the output of ls or find and store the resulting value as elements of an array. This way I can manipulate the array elements as needed.

推荐答案

要回答您的确切问题，请使用以下内容:

To answer your exact question, use the following:

arr=( $(find /path/to/toplevel/dir -type f) )

示例

$ find . -type f
./test1.txt
./test2.txt
./test3.txt
$ arr=( $(find . -type f) )
$ echo ${#arr[@]}
3
$ echo ${arr[@]}
./test1.txt ./test2.txt ./test3.txt
$ echo ${arr[0]}
./test1.txt

但是，如果您只想一次处理一个文件，您可以使用 find 的 -exec 选项(如果脚本有点简单)，或者您可以对 find 返回的内容进行循环:

However, if you just want to process files one at a time, you can either use find's -exec option if the script is somewhat simple, or you can do a loop over what find returns like so:

while IFS= read -r -d $'' file; do
  # stuff with "$file" here
done < <(find /path/to/toplevel/dir -type f -print0)

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