使用 find 命令但排除两个目录中的文件 [英] Use find command but exclude files in two directories

问题描述

我想查找以 _peaks.bed 结尾的文件，但排除 tmp 和 scripts 文件夹中的文件.

I want to find files that end with _peaks.bed, but exclude files in the tmp and scripts folders.

我的命令是这样的:

 find . -type f ( -name "*_peaks.bed" ! -name "*tmp*" ! -name "*scripts*" )

但它没有用.tmp 和 script 文件夹中的文件仍会显示.

But it didn't work. The files in tmp and script folder will still be displayed.

有人对此有想法吗?

推荐答案

以下是您可以使用 find 指定的方法:

Here's how you can specify that with find:

find . -type f -name "*_peaks.bed" ! -path "./tmp/*" ! -path "./scripts/*"

说明:

• find . - 从当前工作目录开始查找(默认递归)
• -type f - 指定 find 你只希望结果中的文件
• -name "*_peaks.bed" - 查找名称以 _peaks.bed
结尾的文件
• <代码>！-path "./tmp/*" - 排除路径以./tmp/
开头的所有结果
• <代码>！-path "./scripts/*" - 同时排除路径以 ./scripts/
开头的所有结果

• find . - Start find from current working directory (recursively by default)
• -type f - Specify to find that you only want files in the results
• -name "*_peaks.bed" - Look for files with the name ending in _peaks.bed
• ! -path "./tmp/*" - Exclude all results whose path starts with ./tmp/
• ! -path "./scripts/*" - Also exclude all results whose path starts with ./scripts/

测试解决方案:

$ mkdir a b c d e
$ touch a/1 b/2 c/3 d/4 e/5 e/a e/b
$ find . -type f ! -path "./a/*" ! -path "./b/*"

./d/4
./c/3
./e/a
./e/b
./e/5

您非常接近，-name 选项仅考虑基本名称，而 -path 考虑整个路径 =)

You were pretty close, the -name option only considers the basename, where as -path considers the entire path =)

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