在 gdb 中使用非路径名启动应用程序 [英] Launch application in gdb with non-path name

问题描述

我正在尝试在 GDB 中启动旧版应用程序，它要求它的 argv[0] 值不包含除字母数字字符以外的任何内容.

每当我在 GDB 中启动程序时，它似乎会在运行程序之前将名称扩展为完整路径，所以我收到如下错误(因为它无法处理斜杠):

找不到/home/user/myapp ..."

是否可以使用相对路径在 GDB 中运行程序，以便它只会看到myapp"?

解决方案

Gdb 正常使用shell命令行运行目标命令

<上一页>执行 program_pathname program_arguments

但它有一个 set exec-wrapper 命令将其更改为

<上一页>exec exec_wrapper program_pathname program_arguments

exec_wrapper 通常是另一个命令，但它可以是 exec 命令接受的选项.

许多 shell(bash、zsh、ksh93)支持 exec 命令的 -a 选项来设置 argv[0].

因此，如果您的 shell 支持 exec -a，您可以执行以下操作以使用 argv[0]== 调用 /home/user/myapp我的应用程序:

(gdb) set exec-wrapper -a myapp

I am trying to launch a legacy application in GDB, and it requires that it's argv[0] value not contain anything other than alphanumeric characters.

Whenever I launch the program in GDB it seems that it expands the name to be the full path before running the program, so I get an error like (because it can't deal with the slashes):

"Cannot find /home/user/myapp ..."

Is it possible to run a program in GDB with a relative path, so that it will just see "myapp"?

解决方案

Gdb normally runs target commands using the shell command line

    exec program_pathname program_arguments

But it has a set exec-wrapper command that will change this to

    exec exec_wrapper program_pathname program_arguments

The exec_wrapper is often another command, but it can be an option that the exec command accepts.

Many shells (bash, zsh, ksh93) support a -a option to the exec command to set argv[0].

So, if your shell supports exec -a, you can do the following to invoke /home/user/myapp with argv[0]==myapp:

(gdb) set exec-wrapper -a myapp

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