Java应用程序启动路径 [英] Java Application Start Path

问题描述

大家好，



最后，我完成了我的毕业设计。我正在增加一些设施。但是，ı遇到了问题。在读取一些文件夹或文件时，.net中有一个代码行。当我们编写Application.StartupPath时...项目指示用户proje\bin\debug文件夹。这样，我想使用相同的工具。我有一个resources.rar文件夹。当用户点击下载应该下载的源链接。但是，我使用自己的路径C：Users / Emre / etc ...



有没有办法解决这个问题？



谢谢。

解决方案

是的。你需要使用相对路径，而不是绝对路径。 br />
应该有一个包ResourceBundle这样做。请检查。



如果你从另一个目的地（某些.net app）链接），你应该使用一个属性来配置一个合适的路径。

为了记录：我相信我在这里回答：提高程序的可移植性 [ ^ ]。

-SA

Hello everyone,

Finally, I finished my graduation project. I am putting some extra facilities. However, ı faced with a problem. There was a code line in .net while reading some folders or files. when we wrote Application.StartupPath... the project directs the user "proje\bin\debug folder. In this manner, I want to use the same facility. I have a resources.rar folder. When the user clicked on the download the source link this should be downloaded. However, I am using my own path C:Users/Emre/etc...

Is there any way to solve this?

Thank you.

解决方案

Yes. You need to use relative paths, not absolute.
There should be a package ResourceBundle for doing so. Please check that.

If you are linking in from another destination (some .net app), you should use a property for configuring a decent path.

For the record: I believe I answered here: Raising the portability of program[^].

—SA

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