window.open() 在第二次调用时返回 undefined 或 null [英] window.open() returns undefined or null on 2nd call

问题描述

我有以下场景:

我点击一个链接:打开一个名为popup"的弹出窗口，在其中加载一个 pdf(在 IE6 中).

I click a link which: opens a popup window called 'popup' which loads a pdf inside of it (in IE6).

在不关闭弹出窗口的情况下，我再次单击该链接，这应该会在弹出窗口中重新打开 pdf，但会抛出一个 javascript 错误:找不到成员

without closing the popup, i click the link again, which should reopen the pdf inside the popup, but instead a javascript error in thrown: member not found

用来打开弹窗的javascript函数是:

the javascript function used to open the popup is:

function openWindow(url, name, props) {
  var windowRef = window.open(url, name, props);
  if (!windowRef.opener) {
    windowRef.opener = self;
  }
  windowRef.focus(); //error at this line, windowRef must be null
  return windowRef;
}

问题:我如何解决这个问题，而不是每次都打开一个新的弹出窗口?

question: how do i get around this, without opening a new popup window every time?

推荐答案

这是互联网上每个人都在使用的 hack:

this is the hack that works that everyone on the internets is using:

function openWindow(url, name, props) {
  if(/*@cc_on!@*/false){ //do this only in IE
    var windowRef = window.open("", name, props);
    windowRef.close();
  }
  var windowRef = window.open(url, name, props);
  if (!windowRef.opener) {
    windowRef.opener = self;
  }
  windowRef.focus();
  return windowRef;
}

这篇关于window.open() 在第二次调用时返回 undefined 或 null的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！