Python Plotly - 多个下拉图，每个都有子图 [英] Python Plotly - Multiple dropdown plots, each of which have subplots

问题描述

问题

我正在尝试结合两个 Python Plotly 功能.其中之一是一个下拉菜单，用户可以在其中切换绘图(

但是你的代码给了我这些情节......

Problem

I'm trying to combine two Python Plotly features. One of them is a drop down menu where a user can switch between plots (link to examples). The other feature is subplots.

My attempt

I have working code that uses the dropdown menu, but it doesn't have subplots. So I looked up how to create subplots here and I thought I could treat a tools.make_subplots figure the same way I treated a go.Box figure. I'm sorry if this seems naive, I'm actually fairly new to Plotly.

However, this attempt is not working at all, I'm seeing two exceptions rise which I've put at the very bottom.

My Working Code (no subplots)

# NOTE: This code goes in between 'START' and 'END' below
traces = []
for data in datas:
    traces.append(go.Box(
                            x=data.index,
                            y=data.values, 
                            showlegend=False
                        ))

My Subplot Code

import plotly.offline as py
import plotly.graph_objs as go
from plotly.offline import init_notebook_mode, iplot, plot
from plotly import tools
init_notebook_mode(connected=True)

### Create individual figures
# START
traces = []
for data in datas:
    fig = tools.make_subplots(rows=1, cols=2)

    trace1 = go.Box(
                    x=data.head(10).index,
                    y=data.head(10).values, 
                    showlegend=False
                )
    trace2 = go.Box(
                    x=data.tail(10).index,
                    y=data.tail(10).values, 
                    showlegend=False
                )   
    fig.append_trace(trace1, 1, 1)
    fig.append_trace(trace2, 1, 2)
    traces.append(fig)
# END

### Create buttons for drop down menu
buttons = []
for i, label in enumerate(labels):
    visibility = [i==j for j in range(len(labels))]
    button = dict(
                 label =  label,
                 method = 'update',
                 args = [{'visible': visibility},
                     {'title': label}])
    buttons.append(button)

updatemenus = list([
    dict(active=-1,
         x=-0.15,
         buttons=buttons
    )
])

layout = dict(title='Title', 
              showlegend=False,
              updatemenus=updatemenus)

fig = dict(data=traces, layout=layout)

iplot(fig, filename='dropdown')

Error 1

'layout' is not allowed in 'scatter'

Path To Error: ['data'][0]['layout']

Error 2

PlotlyError: Invalid 'figure_or_data' argument. Plotly will not be
able to properly parse the resulting JSON. If you want to send this 'figure_or_data' to Plotly anyway (not recommended), you can set 'validate=False' as a plot option.

Here's why you're seeing this error:

'layout' is not allowed in 'scatter'

...

NOTE: When I pass validate=False as a plot option, all I see is an empty plot with drop down menu functionality

解决方案

Naren is right, only one subplots figure needs to be made. And to create the drop down menu effect, you just need to add two traces to the same position like this..

fig.append_trace(trace1, 1, 1)
fig.append_trace(trace2, 1, 1)

Working code

import plotly.offline as py
import plotly.graph_objs as go
from plotly.offline import init_notebook_mode, iplot, plot
from plotly import tools
init_notebook_mode(connected=True)

x = [i for i in range(100)]
df_1 = pd.DataFrame([(i, 1+i) for i in range(100)], columns=["X", "Y"])
df_2 = pd.DataFrame([(i, i*i) for i in range(100)], columns=["X", "Y"])
labels = ["Plus one", "Square"]

### Create individual figures
# START
fig = tools.make_subplots(rows=1, cols=2)

trace1 = go.Bar(
                x=df_1.head(10).X,
                y=df_1.head(10).Y, 
                showlegend=False
            )
trace2 = go.Bar(
                x=df_2.head(10).X,
                y=df_2.head(10).Y, 
                showlegend=False
            )

fig.append_trace(trace1, 1, 1)
fig.append_trace(trace2, 1, 1)

trace1 = go.Bar(
                x=df_1.tail(10).X,
                y=df_1.tail(10).Y, 
                showlegend=False
            )
trace2 = go.Bar(
                x=df_2.tail(10).X,
                y=df_2.tail(10).Y, 
                showlegend=False
            )   
fig.append_trace(trace1, 1, 2)
fig.append_trace(trace2, 1, 2)
# END

### Create buttons for drop down menu
buttons = []
for i, label in enumerate(labels):
    visibility = [i==j for j in range(len(labels))]
    button = dict(
                 label =  label,
                 method = 'update',
                 args = [{'visible': visibility},
                     {'title': label}])
    buttons.append(button)

updatemenus = list([
    dict(active=-1,
         x=-0.15,
         buttons=buttons
    )
])

fig['layout']['title'] = 'Title'
fig['layout']['showlegend'] = False
fig['layout']['updatemenus'] = updatemenus

iplot(fig, filename='dropdown')

Thank you

So much to Naren Murali for your help! Editing your code a bit gave me the answer.

I was looking to create this..

However your code was giving me these plots...

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