递归清空多个文件的命令 [英] Command to empty many files recursively

问题描述

我想递归地清除给定目录的许多日志文件的内容，而不删除每个文件.一个简单的命令可以做到吗?

I would like to clear the content of many log files of a given directory recursively, without deleting every file. Is that possible with a simple command?

我知道我可以做到>logs/logfile.log 一个一个，但是那个文件夹里有很多日志，这不是一目了然.

I know that I can do > logs/logfile.log one by one, but there are lots of logs in that folder, and that is not straightforward.

顺便说一下，我正在使用 macOS Sierra.

I am using macOS Sierra by the way.

推荐答案

感谢@chepner 向我展示了防止文件名中出现双引号的更好方法:

Thanks to @chepner for showing me the better way to protect against double quotes in the file names:

你可以用find来做

find start_dir -type f -exec sh -c '> "$1"' _ {} ;

如果你不想要所有文件，你可以添加额外的限制，比如如果你只想要以 .log 结尾的文件，你可以这样做

And you could add extra restrictions if you don't want all files, like if you want only files ending in .log you could do

find start_dir -type f -name '*.log' -exec sh -c '> "$1"' _ {} ;

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