用 int main(void) 编译失败；main(int argc, char *argv[]) 成功.为什么? [英] Compiling with int main(void) fails; main(int argc, char *argv[]) succeeds. Why?

问题描述

为什么编译具有 int main(void) 主函数的程序与编译具有 int main(int argc, char *argv[]) 的程序不同 main 函数，如果程序不使用命令行传递的参数?

Why would compiling a program which has an int main(void) main function differ from compiling a program which has an int main(int argc, char *argv[]) main function, if the program does not use arguments passed on the command line?

这个操作系统或编译器是特定的吗?我使用 mingw 和 g++ 没有得到相同的结果(这很奇怪，因为wingw 是 gcc 的一个端口).

Is this OS or compiler specific? I do not get the same results using mingw and g++(which is weird isn't it as wingw is a port of gcc).

#include <iostream>
#include"SDL/SDL.h"
int main(void)
{
    return 0;
}

编译命令

g++ test.cpp; #g++ 4.4.5
i586-mingw32msvc-g++ test.cpp; # mingw 4.4.4

错误

(由第二个命令给出.)

Error

(Given by the second command.)

a(main.o):(.text+0x85): undefined reference to `_WinMain@16'

推荐答案

这是 SDL 的事情.在 Windows 上，当你包含 SDL.h 时，main 被重新定义为调用 WinMain 的 SDL_main(真正的入口指向非控制台 Windows 应用程序)，进行一些初始化，最后调用您的主代码.它有一个带有 argc 和 argv 的签名，你几乎需要遵循它，所以 int main() 不起作用.

This is SDL thing. On Windows, when you include SDL.h,main is redefined to SDL_main which calls WinMain (the real entry point in non-console Windows apps), does some initialization and finally calls your main code. It has a signature with argc and argv and you're pretty much required to follow it, so int main() won't work.

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