free 和 malloc 在 C 中是如何工作的? [英] How do free and malloc work in C?

问题描述

I'm trying to figure out what would happened if I try to free a pointer "from the middle" for example, look at the following code:

char *ptr = (char*)malloc(10*sizeof(char));

for (char i=0 ; i<10 ; ++i)
{
    ptr[i] = i+10;
}
++ptr;
++ptr;
++ptr;
++ptr;
free(ptr);

I get a crash with an Unhandled exception error msg. I want to understand why and how free works so that I know not only how to use it but also be able to understand weird errors and exceptions and better debug my codeץ

Thanks a lot

解决方案

When you malloc a block, it actually allocates a bit more memory than you asked for. This extra memory is used to store information such as the size of the allocated block, and a link to the next free/used block in a chain of blocks, and sometimes some "guard data" that helps the system to detect if you write past the end of your allocated block. Also, most allocators will round up the total size and/or the start of your part of the memory to a multiple of bytes (e.g. on a 64-bit system it may align the data to a multiple of 64 bits (8 bytes) as accessing data from non-aligned addresses can be more difficult and inefficient for the processor/bus), so you may also end up with some "padding" (unused bytes).

When you free your pointer, it uses that address to find the special information it added to the beginning (usually) of your allocated block. If you pass in a different address, it will access memory that contains garbage, and hence its behaviour is undefined (but most frequently will result in a crash)

Later, if you free() the block but don't "forget" your pointer, you may accidentally try to access data through that pointer in the future, and the behaviour is undefined. Any of the following situations might occur:

• the memory might be put in a list of free blocks, so when you access it, it still happens to contain the data you left there, and your code runs normally.
• the memory allocator may have given (part of) the memory to another part of your program, and that will presumably have then overwritten (some of) your old data, so when you read it, you'll get garbage which might cause unexpected behaviour or crashes from your code. Or you will write over the other data, causing the other part of your program to behave strangely at some point in the future.
• the memory could have been returned to the operating system (a "page" of memory that you're no longer using can be removed from your address space, so there is no longer any memory available at that address - essentially an unused "hole" in your application's memory). When your application tries to access the data a hard memory fault will occur and kill your process.

This is why it is important to make sure you don't use a pointer after freeing the memory it points at - the best practice for this is to set the pointer to NULL after freeing the memory, because you can easily test for NULL, and attempting to access memory via a NULL pointer will cause a bad but consistent behaviour, which is much easier to debug.

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