使gson使用枚举字符串值而不是常量名称 [英] Make Gson to use Enum string value instead of constant name

查看:30
本文介绍了使gson使用枚举字符串值而不是常量名称的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

有没有办法告诉gson使用字符串值本身,而不是它的Java常量名称? 理想情况下,在gson配置中是全局的,因此它将对所有枚举执行此操作。

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

public class Main {
  public static class Dress {
    public Color color;
  }

  public static enum Color {
    RED("red"),
    BLUE("blue");

    private final String type;
    Color(final String type) { this.type = type; }

    public String toString() { return type; }
  }

  public static void main(String[] args) throws InterruptedException {
    Dress dress = new Dress();
    dress.color = Color.RED;

    GsonBuilder builder = new GsonBuilder();
    builder.setPrettyPrinting();
    Gson gson = builder.create();
    System.out.println(gson.toJson(dress));
    // ==> { "color": "RED" }
  }
}

它打印{ "color": "RED" }而不是{ "color": "red" }

推荐答案

创建自定义序列化程序,如下所示:

public class EnumSerializer<T extends Enum<T>>
                    implements JsonSerializer<T> {
    @Override
    public JsonElement serialize(T src, Type typeOfSrc,
                JsonSerializationContext context) {
        return new JsonPrimitive(src.toString());
    }
}

按如下方式注册:

builder.registerTypeAdapter(Color.class, new EnumSerializer<>());
// there is a reason for generics: that way you can easily register it to 
// other Enum types also, for example:
// builder.registerTypeAdapter(SomeEnum.class, new EnumSerializer<>());

如果需要将其应用于多个或所有Enum,并且不希望将其分别注册到每个Enum,则可以使用TypeAdapterFactory(稍微复杂一点)。首先,您需要TypeAdapter:

public class EnumTypeAdapter<T extends Enum<T>> extends TypeAdapter<T> {
    @Override
    public void write(JsonWriter out, T value) throws IOException {
        out.jsonValue(value.toString());
    }
    @Override
    public T read(JsonReader in) throws IOException {
        return null;
    }
}

然后工厂:

public static class EnumTypeAdapterFactory implements TypeAdapterFactory {
    @Override
    // Actually it might be easier to just make EnumTypeAdapter non-generic
    // but on the other hand it might be better if used in some other contexts
    // and in some other ways. Thus these suppressions
    @SuppressWarnings({"rawtypes", "unchecked"})
    public <T> TypeAdapter<T> create(Gson gson, TypeToken<T> type) {
        // This if applies to all Enums. Change if not wanted.            
        if(Enum.class.isAssignableFrom(type.getRawType())) {
            return new EnumTypeAdapter();
        } else {
            return  null;                
        }
    }
}

并注册:

builder.registerTypeAdapterFactory(new EnumTypeAdapterFactory());

这篇关于使gson使用枚举字符串值而不是常量名称的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆