使iPhone发送URLEncoded字符串而不是JSON [英] Make iPhone to send URLEncoded string instead of JSON

问题描述

我有一个Symfony2服务器从JQuery接收HTTP POSTs：

I have a Symfony2 server that receives HTTP POSTs from JQuery using:

var myJSON = {key1: "value1", key2: ["value2", "value3"]};
$.post(myURL, {myJSON}, function(json){}, "json");

这完美无缺，在内部转换一个Request对象的json，一旦在Controller中，使用 $ this-> getRequest（） - > get（'key1'）或 get（'key2'）获得一些形式良好的PHP对象，无需额外的工作。

This works perfect and internally converts the json in a Request object that, once in the Controller, I can get straightforward with $this->getRequest()->get('key1') or get('key2') obtaining some well formed PHP objects with no additional work.

所以我有一个完整的应用程序与JQuery和Symfony2这样工作。

So I have a complete application with JQuery and Symfony2 working this way.

现在我需要使用iPhone SDK和Objective C开发一个移动客户端。

Now I need to develop a mobile client using iPhone SDK and Objective C.

但是我发现要做的是发送JSON并在服务器中使用json_decode将其转换为PHP对象一次。这些例子使用这段代码：

But all examples I am finding to do it send the JSON and convert it to PHP objects once in the server using json_decode. Those examples use this piece of code:

NSArray *myArray = [NSArray arrayWithObjects: @"Value2", @"Value3", nil];
NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys: @"Value1", @"key1", myArray, @"Value2"];
NSData* requestData = [NSJSONSerialization dataWithJSONObject:myDict options:NSJSONWritingPrettyPrinted error:&error];
NSLog(@"JSON string:%@", [[NSString alloc] initWithData:requestData encoding:NSUTF8StringEncoding]); // To check that the conversion to JSON is indeed being performed perfectly!!

[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"XMLHttpRequest" forHTTPHeaderField:@"X-Requested-With"];

[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

这会将JSON数据直接发送到服务器，并且 $ this-> ; getRequest（） - > get（'key1'） 返回null 。此方法需要在HTTP请求的内容正文中接收该JSON，并使用PHP json_decode 来管理数据。

This sends directly the JSON data to the server and the $this->getRequest()->get('key1') returns null. This approach expects to receive that JSON thata in the content body of the HTTP Request and do a PHP json_decode to manage the data.

好吧，我可以让它修改我的API来检查什么样的数据来了， json_decoding 如果是JSON或 getRequest 如果它是URLEncode。

Ok, I can get it modifying my "API" to check what kind of data is coming and json_decoding if it is JSON or the getRequest thing if it is URLEncode.

但在做这种解决方法之前，是不是有一个简单的方法来获得 JQuery 并行转换获得链接的 NSDictionaries 和 NSArrays 为 URLEncoded 并以 application / x-www-form-urlencoded 的形式发送到服务器，始终在 getRequest（） - > get（'key1'） style？

But before doing that workaround, isn't there an easy way to get a JQuery parallel conversion getting the linked NSDictionaries and NSArrays to be URLEncoded and sent to the server as application/x-www-form-urlencoded to get the data in the server always in the getRequest()->get('key1') style?

推荐答案

这个工作完美，内部转换json在请求
对象，一旦在控制器，我可以直接用
$ this-> getRequest（） - > get（' key1'）或get（'key2'）获取一些井
形成没有额外工作的PHP对象。

This works perfect and internally converts the json in a Request object that, once in the Controller, I can get straightforward with $this->getRequest()->get('key1') or get('key2') obtaining some well formed PHP objects with no additional work.

Symfony不在内部转换你的JSON在一个Request对象！
如果你想要一种处理数据的方法，你只需要发送一种类型的数据（json或x-www-url-encoded）。我在上一个问题写了你可以编码iOS发送数据与x-www-url编码，但你也可以在jQuery.post和iOS中发送JSON。然后只能实现：

Symfony does not internally convert your json in a Request object! If you want one way for working with data you need to send data with only one type (json or x-www-url-encoded). I wrote you in the previous question that you can encode iOS to send data with x-www-url-encoded but you can also send JSON in jQuery.post and from iOS. And then you must implement only:

$data = json_decode($this->getRequest()->getContent());

要在JS中发送JSON数据，您需要下一个代码：

To send JSON data in your JS you need next code:

$.ajax({
    type: "POST",
    url: myURL,
    data: JSON.stringify(myJSON),
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function(json){},
});

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