计算事件循环中的活动任务数 [英] Count active tasks in event loop
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问题描述
如何找出事件循环中有多少活动任务? 在文档中我只找到asyncio.Task.all_tasks(),但它是简单的递增计数器:
import asyncio
async def coro():
await asyncio.sleep(1)
async def main():
tasks = []
print('Tasks count: ', len(asyncio.Task.all_tasks()))
for idx in range(3):
task = asyncio.ensure_future(coro())
tasks.append(task)
print('Tasks count: ', len(asyncio.Task.all_tasks()))
await asyncio.gather(*tasks)
print('Tasks count: ', len(asyncio.Task.all_tasks()))
loop = asyncio.get_event_loop()
loop.run_until_complete(main())
输出:
Tasks count: 1
Tasks count: 2
Tasks count: 3
Tasks count: 4
Tasks count: 4
预期输出:
Tasks count: 1
Tasks count: 2
Tasks count: 3
Tasks count: 4
Tasks count: 1
推荐答案
all_tasks
返回所有注册的任务,包括已完成的任务。您可以通过done()
对任务进行过滤操作来获取活动的任务:
import asyncio
async def coro():
await asyncio.sleep(1)
async def main():
tasks = []
print('Tasks count: ', len(asyncio.Task.all_tasks()))
for idx in range(3):
task = asyncio.ensure_future(coro())
tasks.append(task)
print('Tasks count: ', len(asyncio.Task.all_tasks()))
await asyncio.gather(*tasks)
print('Tasks count: ', len(asyncio.Task.all_tasks()))
print('Active tasks count: ', len(
[task for task in asyncio.Task.all_tasks() if not task.done()])
)
loop = asyncio.get_event_loop()
loop.run_until_complete(main())
哪些输出:
Tasks count: 1
Tasks count: 2
Tasks count: 3
Tasks count: 4
Tasks count: 4
Active tasks count: 1
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