在一个命令中合并单个对象下的多个对象和添加同级对象 [英] Merge multiple objects under a single object and add sibling object in one command
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问题描述
所以我有三个文件:
cats.json
{
"cats": [
{
"name": "fluffles",
"age": 10,
"color": "white"
}
]
}
dogs.json
{
"dogs": [
{
"name": "sam",
"age": 5,
"color": "black and white"
},
{
"name": "rover",
"age": 2,
"color": "brown and white"
}
]
}
Snakes.json
{
"snakes": [
{
"name": "noodles",
"age": 10,
"color": "green"
}
]
}
我想将它们合并在一起,放在一个动物对象下。我发现这将合并文件:
jq -s '{"animals": .} ' cats.json dogs.json snakes.json > animals.json
{
"animals": [
{
"cats": [
{
"name": "fluffles",
"age": 10,
"color": "white"
}
]
},
{
"dogs": [
{
"name": "sam",
"age": 5,
"color": "black and white"
},
{
"name": "rover",
"age": 2,
"color": "brown and white"
}
]
},
{
"snakes": [
{
"name": "noodles",
"age": 10,
"color": "green"
}
]
}
]
}
现在我有一个额外的对象:
owners.json
{
"owners": [
"peter",
"william",
"sally"
]
}
我要使用
将其合并到同一文件中jq -s '.[0] + .[1]' animals.json owners.json
我可以用一个jq
命令同时执行这两个操作吗?
jq -s '{"animals": .} ' cats.json dogs.json snakes.json > animals.json
jq -s '.[0] + .[1]' animals.json owners.json
结果如下:
{
"animals": [
{
"cats": [
{
"name": "fluffles",
"age": 10,
"color": "white"
}
]
},
{
"dogs": [
{
"name": "sam",
"age": 5,
"color": "black and white"
},
{
"name": "rover",
"age": 2,
"color": "brown and white"
}
]
},
{
"snakes": [
{
"name": "noodles",
"age": 10,
"color": "green"
}
]
}
],
"owners": [
"peter",
"william",
"sally"
]
}
推荐答案
假设您有一个(先验的)不确定或大量的动物类型,并且只有一个owners
文件。在这种情况下,不使用-s
选项会更好(节省内存),并且使用所有者文件作为第一个数据文件来调用JQ会更容易,例如
jq -n -f program.jq owners.json $(ls *.json | grep -v owners.json)
其中Program.jq包含程序,例如:
input as $owners | {$owners, animals: [inputs]}
(请注意{"owners": $owners}
如何缩写。)
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