为什么Pivot_Long()在其输出中只嵌套四个整数值 [英] Why pivot_longer() nests simply four integer values in its output
本文介绍了为什么Pivot_Long()在其输出中只嵌套四个整数值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想知道为什么我下面的pivot_longer()
调用在value
列下返回嵌套输出?
foo <- function(){
n_subj = 5
n_trials = 20
subj_intercepts = rnorm(n_subj, 0, 1)
slope = .6
mx = 30
data = data.frame(subject = rep(1:n_subj, each=n_trials),
intercept = rep(subj_intercepts, each=n_trials)) %>%
mutate(x = rnorm(n(), mx, 1),
y = intercept + slope*(x-mean(x)) + rnorm(n(), 0, 1))
mlm = coef(summary(lmer(y ~ x + (1|subject), data=data)))[2,1]
ols = coef(summary(lm(y ~ x, data=data)))[2,1]
list(ols=ols, mlm=mlm)
}
kk <- data.frame(t(replicate(2, foo())))
pivot_longer(kk, everything())
# name value
# <chr> <list>
#1 ols <dbl [1]>
#2 mlm <dbl [1]>
#3 ols <dbl [1]>
#4 mlm <dbl [1]>
推荐答案
您正在函数中创建一个列表:Add/Wrapunlist
在函数代码的末尾添加/换行以获得tibble
:
foo <- function(){
n_subj = 5
n_trials = 20
subj_intercepts = rnorm(n_subj, 0, 1)
slope = .6
mx = 30
data = data.frame(subject = rep(1:n_subj, each=n_trials),
intercept = rep(subj_intercepts, each=n_trials)) %>%
mutate(x = rnorm(n(), mx, 1),
y = intercept + slope*(x-mean(x)) + rnorm(n(), 0, 1))
mlm = coef(summary(lmer(y ~ x + (1|subject), data=data)))[2,1]
ols = coef(summary(lm(y ~ x, data=data)))[2,1]
unlist(list(ols=ols, mlm=mlm))
}
输出
name value
<chr> <dbl>
1 ols 0.600
2 mlm 0.581
3 ols 0.441
4 mlm 0.528
这篇关于为什么Pivot_Long()在其输出中只嵌套四个整数值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文