在Python中检测按键，其中每次迭代可能需要几秒钟以上的时间？ [英] detect key press in python, where each iteration can take more than a couple of seconds?

问题描述

编辑：以下使用keyboard.on_press(Callback，Suppress=False)的答案在ubuntu中运行正常，没有任何问题。 但在Redhat/Amazon Linux中，它无法工作。

我已经使用了thread

中的代码片段

import keyboard  # using module keyboard
while True:  # making a loop
    try:  # used try so that if user pressed other than the given key error will not be shown
        if keyboard.is_pressed('q'):  # if key 'q' is pressed 
            print('You Pressed A Key!')
            break  # finishing the loop
    except:
        break  # if user pressed a key other than the given key the loop will break

但上面的代码要求每次迭代在纳秒内执行。在以下情况下失败：

import keyboard  # using module keyboard
import time
while True:  # making a loop
    try:  # used try so that if user pressed other than the given key error will not be shown
        print("sleeping")
        time.sleep(5)
        print("slept")
        if keyboard.is_pressed('q'):  # if key 'q' is pressed 
            print('You Pressed A Key!')
            break  # finishing the loop
    except:
        print("#######")
        break  # if user pressed a key other than the given key the loop will break

推荐答案

您可以在keyboard模块中使用事件处理程序来达到预期效果。

一个这样的处理程序keyboard.on_press(callback, suppress=False)： 它为每个key_down事件调用一个回调。 有关详细信息，请访问keyboard docs

以下是您可以尝试的代码：

import keyboard  # using module keyboard
import time

stop = False
def onkeypress(event):
    global stop
    if event.name == 'q':
        stop = True

# ---------> hook event handler
keyboard.on_press(onkeypress)
# --------->

while True:  # making a loop
    try:  # used try so that if user pressed other than the given key error will not be shown
        print("sleeping")
        time.sleep(5)
        print("slept")
        if stop:  # if key 'q' is pressed 
            print('You Pressed A Key!')
            break  # finishing the loop
    except:
        print("#######")
        break  # if user pressed a key other than the given key the loop will break

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