铸造float.MaxValue龙抛出的异常？ [英] Casting float.MaxValue to Long throws exception?

问题描述

试图让float.MaxValue的整数部分，但它抛出错误？

Trying to get integer part of float.MaxValue but it is throwing error?

        long l = Convert.ToInt64(float.MaxValue);
        Console.WriteLine(l);

错误： 算术运算导致溢出。

Error: Arithmetic operation resulted in an overflow.

推荐答案

在 浮动 是3.4E + 38，而一的 长 是9.2 E + 18。因此， float.MaxValue 将不适合进入长。

借助 Convert.ToInt64 方法抛出发生OverflowException 当您指定的值比 Int64.MaxValue 或小于 Int64.MinValue

The Convert.ToInt64 method throws an OverflowException when you specify a value that is greater than Int64.MaxValue or less than Int64.MinValue

如果你只是想获得 float.MaxValue 的整数值，请参阅相关的答案的这个问题。但要注意，即使剥夺了浮点，一个浮动的最大值仍然不适合在长数据类型。

If you just want to get the integer value of float.MaxValue, see the relevant answers to this question. But note that even stripped of the floating point, the maximum value of a float will still not fit in the long data type.

编辑：的原因，一个浮动（32位值）比一个更高的最大值长（64位值）是由于的方式浮点数被内部重新由计算机psented $ P $。浮点值类型可容纳值所能比的定点和整数类型的更广泛的范围，虽然这更大的范围在precision为代价来实现。

The reason that a float (a 32-bit value) has a higher maximum value than a long (a 64-bit value) is because of the way floating point numbers are internally represented by the computer. Floating point value types can hold wider ranges of values than can fixed-point and integer types, although this greater range is achieved at the expense of precision.

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