程序抛出异常 [英] Program throwing exception

问题描述

我正在编写一个程序，允许用户输入一个句子，然后存储在一个字符串中，然后程序将删除句子中的所有句子，然后在输出之前创建字符串中每个单词的列表列表到控制台。

I am writing a program that allows the user to enter a sentence which then gets stored in a string and then the program will remove any full stops in the sentence and then create a list of each individual word in the string before outputting that list to the console.

程序运行正常，只要句子中只有一个完整句，但如果有任何更多，它抛出此异常：

the program is working perfectly as long as there is only 1 full stop in the sentence but if there are any more than that it throws this exception:

在Project6.exe的0x7696B727处的未处理异常：Microsoft C ++异常：std :: out_of_range在内存位置0x0022F8B8。

Unhandled exception at at 0x7696B727 in Project6.exe: Microsoft C++ exception: std::out_of_range at memory location 0x0022F8B8.

然后如果我继续运行它它会抛出：

and then if I continue to run it it throws:

运行时检查失败＃0 - ESP的值没有正确保存在一个函数调用。这通常是调用用一个调用约定声明的函数的结果，该函数指针用不同的调用约定声明。

Run-Time Check Failure #0 - The value of ESP was not properly saved across a function call. This is usually a result of calling a function declared with one calling convention with a function pointer declared with a different calling convention.

任何建议？ （在任何人问之前，我知道你通常只有1句全句，但我需要做超过1作为测试的一部分。

any suggestions? (and before anyone asks, i know you usually only have 1 full stop in a sentence but i need to do it with more than 1 as part of testing.

这里是代码：

 #include <iostream>
 #include <string>

 using namespace std

 string sSentence; // sets up a string variable called sSentence

 int i = 0;

 void RemoveFullStop()
 {
    while(sSentence.find (".") != string::npos) // the program runs this loop until it cannot            find any more full stops in the string
{
        i = sSentence.find("." , i); // find the next full stop in the string and get the      character count of the space and place it in the variable i
        sSentence.replace(i,1,""); // remove the full stop
    }
}

void ListWords()
{
    while(sSentence.find (" ") != string::npos) // the program runs this loop until it cannot find any more spaces in the string
    {
        i = sSentence.find(" " , i); // find the next space in the string and get the character count of the space and place it in the variable i

        // cout << i << endl; // output the contents of iWordSpace to the console (used for debugging - no longer used)

        sSentence.replace(i,1,"\n");

        // cout << sSentence << endl; // output the contents of iWordSpace to the console (used for debugging - no longer used)

        }
    }

   int main()
   {
        getline(cin, sSentence); // get user input and store it in sSentence (using the getline     function so the .find operation works correctly)

        RemoveFullStop(); // calls the RemoveFullStop void function that removes all full stops from the string

        ListWords(); // calls the ListWords void function that splits the string into a list of words

        cout << endl; // formatting line
        cout << "The words that were in the sentence were:" << endl;
        cout << endl; // formatting line
        cout << sSentence << endl;
        cout << endl; // formatting line

    system("pause");

    return 0;
}

推荐答案

当ListWords运行中 sSentence.find（，i）时，i的值不为0，因为它已在 RemoveFullStop c $ c>。要解决此问题，请先删除 int i = 0; ，然后将其添加到 RemoveFullStop（）和 ListWords（）

此外，虽然这只是一个风格的东西，不会影响你的代码运行能力，我不会调用这个变量 i 作为 i，j，k 通常意味着计数器。

The reason this happens is that when sSentence.find(" " , i) in ListWords runs, i's value is not 0 because it was already defined in RemoveFullStop(). To fix this, first remove int i = 0;, then add it to RemoveFullStop() and ListWords()
Also, while this is just a style thing and won't effect your codes ability to run, I wouldn't call this variable i as i,j,k usually imply counters. Call this variable something more appropriately descriptive.

这里是相关的代码，因为它应该是。

Here is the relevant code as it should be.

 using namespace std
 string sSentence; 

void RemoveFullStop()
{
    int charPlace = 0;
    while(sSentence.find (".") != string::npos) 
    {
        charPlace = sSentence.find("." , charPlace); 
        sSentence.replace(charPlace,1,""); 
    }
}

void ListWords()
{
    int charPlace = 0;
    while(sSentence.find (" ") != string::npos) 
    {
        charPlace = sSentence.find(" " , charPlace);
        sSentence.replace(charPlace,1,"\n");
    }
}

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