如何接受一个文件POST - ASP.Net MVC 4的WebAPI [英] How To Accept a File POST - ASP.Net MVC 4 WebAPI

问题描述

我使用asp.net的MVC 4的WebAPI测试建立一个休息服务。我需要能够接受张贴的图片/文件从客户端应用程序。这是可能使用的WebAPI？下面是我如何行动目前正在使用。有谁知道一个例子这应该是如何工作的？

  [HttpPost]
公共字符串ProfileImagePost（HttpPostedFile profileImage）
{
    字符串[] =扩展{.JPG，.JPEG，名为.gif，.BMP，png格式};
    如果（extensions.Any（X =＆GT;！x.Equals（Path.GetExtension（profileImage.FileName.ToLower（）），StringComparison.OrdinalIgnoreCase）））
    {
        抛出新的Htt presponseException（无效的文件类型，则httpStatus code.BadRequest）;
    }    //其他code到这里    返回/path/to/image.png
}
 

解决方案

看<一个href=\"http://www.asp.net/web-api/overview/working-with-http/sending-html-form-data,-part-2\">http://www.asp.net/web-api/overview/working-with-http/sending-html-form-data,-part-2,虽然我觉得文章使它看起来有点复杂得多，它确实是。

基本上，

 公共任务＆LT; Htt的presponseMessage＆GT; PostFile（）
{
    HTT prequestMessage请求= this.Request;
    如果（！request.Content.IsMimeMultipartContent（））
    {
        抛出新的Htt presponseException（的HTTPStatus code.UnsupportedMediaType）;
    }    串根= System.Web.HttpContext.Current.Server.MapPath（〜/ App_Data文件/上传）;
    VAR提供商=新MultipartFormDataStreamProvider（根）;    VAR任务= request.Content.ReadAsMultipartAsync（供应商）。
        ContinueWith＆LT; Htt的presponseMessage＆GT;（O = GT;
    {        字符串文件1 = provider.BodyPartFileNames.First（）值。
        //这是该文件被保存在服务器上的文件名        返回新的Htt presponseMessage（）
        {
            内容=新的StringContent（文件上传。）
        };
    }
    ）;
    返回任务;
}
 

I'm using asp.net mvc 4 webapi beta to build a rest service. I need to be able to accept POSTed images/files from client applications. Is this possible using the webapi? Below is how action I am currently using. Does anyone know of an example how this should work?

[HttpPost]
public string ProfileImagePost(HttpPostedFile profileImage)
{
    string[] extensions = { ".jpg", ".jpeg", ".gif", ".bmp", ".png" };
    if (!extensions.Any(x => x.Equals(Path.GetExtension(profileImage.FileName.ToLower()), StringComparison.OrdinalIgnoreCase)))
    {
        throw new HttpResponseException("Invalid file type.", HttpStatusCode.BadRequest);
    }

    // Other code goes here

    return "/path/to/image.png";
}

解决方案

see http://www.asp.net/web-api/overview/working-with-http/sending-html-form-data,-part-2, although I think the article makes it seem a bit more complicated than it really is.

Basically,

public Task<HttpResponseMessage> PostFile() 
{ 
    HttpRequestMessage request = this.Request; 
    if (!request.Content.IsMimeMultipartContent()) 
    { 
        throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType); 
    } 

    string root = System.Web.HttpContext.Current.Server.MapPath("~/App_Data/uploads"); 
    var provider = new MultipartFormDataStreamProvider(root); 

    var task = request.Content.ReadAsMultipartAsync(provider). 
        ContinueWith<HttpResponseMessage>(o => 
    { 

        string file1 = provider.BodyPartFileNames.First().Value;
        // this is the file name on the server where the file was saved 

        return new HttpResponseMessage() 
        { 
            Content = new StringContent("File uploaded.") 
        }; 
    } 
    ); 
    return task; 
} 

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