渲染查看HTML code这是在asp.nt MVC的控制器产生 [英] Rendering html code in view which is generated in controller of asp.nt mvc

问题描述

我实现基于角色的菜单。我必须动态生成从数据库菜单。我从哪里可以得到映射到该角色的功能角色的特征映射表。一旦我得到了我要生成HTML菜单以＆lt; UL＆GT;和＆lt;立GT; 。我能得到的建议是到要如何做。我的意思是在生成控制器中的HTML脚本，并使其在各自的观点。请帮忙。任何建议表示欢迎。

I am implementing a role based menu. I have to generate the menu from the database dynamically. I have a role-feature mapping table from where I can get the features that are mapped to the role. Once I get that I have to generate the HTML menus with <ul> and <li>. Can I get suggestion as to how that be done. I mean generating the HTML script in controller and rendering it on to the respective view. Please help. Any suggestion is welcomed.

<ul id="menu">
  <li>
    @Html.ActionLink("Home", "Dashboard", "User")
  </li>
  <li>
    <a href="#"><span>User</span></a>
    <ul>
      <li>@Html.ActionLink("Create User", "CreateUser", "User")</li>
    </ul>
  </li>
  <li>
    <a href="#"><span>Report</span></a>
    <ul>
      <li>@Html.ActionLink("ABC Report", "ABC", "Report")</li>
      <li>@Html.ActionLink("User Report", "UserReport", "Report")</li>
    </ul>
  </li>
  <li>
    <a href="#"><span>XYZ</span></a>
    <ul>
      <li>@Html.ActionLink("XYZ1", "XYZ1", "XYZ")</li>
      <li>@Html.ActionLink("XYZ2", "XYZ2", "XYZ")</li>
      <li>@Html.ActionLink("XYZ3", "XYZ3", "XYZ")</li>
      <li>@Html.ActionLink("XYZ4", "XYZ4", "XYZ")</li>
    </ul>
  </li>                      
</ul>

以上HTML我必须建立在控制器和渲染视图。

Above HTML I have to build in controller and render to the view.

推荐答案

我建议创建一个菜单类，如下

I suggest to create a Menu class as below

public class Menu
{
   public string Text {get;set;}
   public string Controller {get;set;}
   public string Action {get;set;}
}

然后在视图模型添加类型的属性菜单列表 列表＆LT;菜单＆gt; 然后填写该集合在你的控制器动态地从你的数据库

then in your viewModel add a property MenuList of type List<Menu> then fill that collection in your controller dynamically from your database

然后更改您的视图如下

<a href="#"><span>XYZ</span></a>
<ul>
  @for(var menu in Model.MenuList)
  {
     <li>@Html.ActionLink(menu.Text, menu.Action, menu.Controller)</li>
  }
</ul>

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