为什么离开做＆QUOT; MOV ESP，EBP＆QUOT;在x86汇编？ [英] Why does leave do "mov esp,ebp" in x86 assembly?

问题描述

有人说，在离开指令是一样的：

It's said that the leave instruction is the same as :

mov esp,ebp
pop ebp

但是，什么是 MOV ESP，EBP 这里？它似乎没有有效的给我...

But what is mov esp,ebp here for? It doesn't seem valid to me...

推荐答案

MOV ESP，EBP 设置堆栈指针在底座的地址，有效地释放了整体框架。 （不要忘记，这是英特尔的语法，目标是第一位的。）如果你没有做到这一点，一旦你叫 RET ，你仍然会使用被叫函数的栈帧与你通话功能，具有crashtastic后果。

mov esp,ebp sets the stack pointer to the base frame address, effectively releasing the whole frame. (Don't forget that this is Intel syntax, the destination comes first.) If you didn't do it, once you call ret, you would still be using the called function's stack frame with your calling function, with crashtastic consequences.

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