问题x86汇编转换成整数ASCII code [英] Problem converting integer to ASCII code in x86 assembly

问题描述

我想用下面的code为整数转换成斧来ASCII codeS。但运行它输出515，而不是513如我所料。哪里的错误？

  STK段
    DW 32 DUP（0）
STK结束
DTS段
    posnum分贝6 DUP（0）; 0℃; X＆下; 65536;
DTS结束
CDS段
    假设CS：CDS，DS：DTS，SS：STK
    主要PROC远     MOV AX，赛格DTS
     MOV DS，AX
     MOV ES，AX
     异斧，斧     MOV AX，513     MOV DI，抵消posnum     呼叫ConvertPositive     MOV啊，09H
     MOV DX，偏移posnum
     INT 21H
    main_finish：
        MOV啊，08H
        INT 21H
        MOV AX，4c00h
        INT 21H
    主要ENDP
CDS完特效片段
    假设CS：特效
    ConvertPositive PROC远
        XOR DX，DX
        XOR CX，CX
        MOV BL，10
        MOV BH，0
        divloop：
            MOV DX，0
            DIV BX
            添加DL，30H
            MOV字节PTR [SI]，DL
            INC CL
            INC SI
            CMP斧，0
            JNE divloop
        enddiv：
            十二月SI
            复制：
                STD
                LODSB
                CLD
                STOSB
            循环副本
            MOV字节PTR [二]，$
        RET
    ConvertPositive ENDP
特效结束
主要结束
 

解决方案

SI 未初始化。它应指向分配相反的顺序数字的缓冲区。

I am trying to use the code below to convert an integer in ax to ASCII codes. But running it outputs 515, rather than 513 as I expected. Where is the error?

stk segment
    dw 32 dup(0)
stk ends
dts Segment
    posnum db 6 dup(0) ;0<x<65536;
dts ends
cds Segment
    Assume cs:cds , ds:dts,ss:stk
    Main Proc Far

     mov ax,seg dts
     mov ds,ax
     mov es,ax
     xor ax,ax

     mov ax,513

     mov di,offset posnum

     Call ConvertPositive

     mov ah,09h
     mov dx ,offset posnum
     int 21h
    main_finish:
        mov ah,08h
        int 21h
        mov ax,4c00h
        int 21h
    Main endp
cds Ends

procs segment
    assume cs:procs
    ConvertPositive proc far
        xor dx,dx
        xor cx,cx
        mov bl,10
        mov bh,0
        divloop:
            mov dx,0
            div bx
            add dl,30h
            mov byte ptr [si],dl
            inc cl
            inc si
            cmp ax,0
            jne divloop
        enddiv:
            dec si
            copy:
                std
                LODSB
                cld
                STOSB   
            loop copy
            mov byte ptr [di],'$'
        ret
    ConvertPositive endp
procs ends
end Main

解决方案

SI is not initialized. It should point to a buffer allocated for the reverse order digits.

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