我在学习上的OS X 10.6 x86汇编，我怎么编？ [英] I'm learning x86 assembly on OS X 10.6, how do I compile?

问题描述

我要学习x86汇编语言在Mac OS X.
我使用的指令编译表彰窗组件文件。
但是，我有几个错误，我不知道我怎样才能通过。

I'm about to learn x86 assembly language on Mac OS X. I'm using as instruction to compile assembly file in commend window. But I have several errors and I don't know how I can get through.

下面是错误和我的装配code，这是很简单的。

Here are the errors and my assembly code, which is quite simple.

**ung-mi-lims-macbook-pro:pa2 ungmi$ as swap.s
swap.s:16:Unknown pseudo-op: .type
swap.s:16:Rest of line ignored. 1st junk character valued 115 (s).
swap.s:19:suffix or operands invalid for `push'
swap.s:46:suffix or operands invalid for `pop'
ung-mi-lims-macbook-pro:pa2 ungmi$** 

和源是

.text
        .align 4
.globl  swap
        .type swap,@function

swap:
        pushl   %ebp
        movl    %esp, %ebp

        movl    %ebp, %esp
        popl    %ebp
        ret

和我搜索了一些解决方案，这是我必须把-arch i386的比

and I searched some solution which is I have to put -arch i386 than

**ung-mi-lims-macbook-pro:pa2 ungmi$ as -arch i386 swap.s
swap.s:16:Unknown pseudo-op: .type
swap.s:16:Rest of line ignored. 1st junk character valued 115 (s).
ung-mi-lims-macbook-pro:pa2 ungmi$** 

你能帮助我吗？只要让我知道我需要编译汇编文件。
我有X code处已经和我宁愿与表彰窗口和vi编辑器做到这一点。

Could you help me out? Just let me know what I need to compile assembly file. I have XCode already and I'd rather to do this with commend window and vi editor.

推荐答案

您code是32位​​汇编​​。雪豹编译是64位的默认，但你可以使用的gcc -m32 编译32位code。当然也有也可以传递到选项和 LD ，但我发现，只记得该选项 GCC 已经足够了，因为它是一个前端的所有这些事情。

Your code is 32-bit assembly. Compilation on Snow Leopard is 64-bit by default, but you can use gcc -m32 for compiling 32-bit code. There are of course also options that you can pass to as and ld but I found that remembering only the option for gcc was enough, since it is a front-end to all these things.

使用GCC向您展示装配code，工程的一个例子：在文件test.c的键入一个最小的C函数，并使用的gcc -S test.c以生产装配文件test.s。

Use gcc to show you an example of assembly code that works: type a minimal C function in file test.c and use gcc -S test.c to produce the assembly in file test.s.

例如：

int x;

void f(void)
{
  int i;
  for (i = 0; i < 5; i++)  x = x + 1;
}

编译汇编本豹纹Mac上：

is compiled in assembly on this Leopard Mac:

    .text
.globl _f
_f:
    pushl   %ebp
    movl    %esp, %ebp
    subl    $24, %esp
    call    L6
"L00000000001$pb":
L6:
    popl    %ecx
    movl    $0, -12(%ebp)
    jmp L2
L3:
    leal    L_x$non_lazy_ptr-"L00000000001$pb"(%ecx), %eax
    movl    (%eax), %eax
    movl    (%eax), %eax
    leal    1(%eax), %edx
    leal    L_x$non_lazy_ptr-"L00000000001$pb"(%ecx), %eax
    movl    (%eax), %eax
    movl    %edx, (%eax)
    leal    -12(%ebp), %eax
    incl    (%eax)
L2:
    cmpl    $4, -12(%ebp)
    jle L3
    leave
    ret
.comm _x,4,2
    .section __IMPORT,__pointers,non_lazy_symbol_pointers
L_x$non_lazy_ptr:
    .indirect_symbol _x
    .long   0
    .subsections_via_symbols

您可以把它简单的通过gcc选项-fno-PIC：

You can make it simpler by using gcc option -fno-PIC:

    .text
.globl _f
_f:
    pushl   %ebp
    movl    %esp, %ebp
    subl    $24, %esp
    movl    $0, -12(%ebp)
    jmp L2
L3:
    movl    _x, %eax
    incl    %eax
    movl    %eax, _x
    leal    -12(%ebp), %eax
    incl    (%eax)
L2:
    cmpl    $4, -12(%ebp)
    jle L3
    leave
    ret
.comm _x,4,2
    .subsections_via_symbols

在Snow Leopard中，你会得到64位的组件（AMD64）。你可以通过使用gcc的-m64选项得到豹同样的事情，你可以得到雪豹同样的事情，你会在Leopard与-m32选项得到运行的gcc。

On Snow Leopard you will get 64-bit assembly (amd64). You could get the same thing on Leopard by using the -m64 gcc option, and you can get on Snow Leopard the same thing you'd get running gcc on Leopard with the -m32 option.

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