如何通过UDP发送音频流中的Java？ [英] How to send audio stream via UDP in java?

问题描述

我有一个问题，我已设置的MediaLocator为麦克风输入，然后创建播放器。
我需要抓住从麦克风的声音，连接$ C $其C到一些质量较低的流，并把它作为通过UDP数据报包。
这里的code，我发现大部分在线和它适应了我的应用程序：

I have a problem, i have set MediaLocator to microphone input, and then created Player. I need to grab that sound from the microphone, encode it to some lower quality stream, and send it as a datagram packet via UDP. Here's the code, i found most of it online and adapted it to my app:

public class AudioSender extends Thread {

private MediaLocator ml = new MediaLocator("javasound://44100");
private DatagramSocket socket;
private boolean transmitting;
private Player player;
TargetDataLine mic;
byte[] buffer;
private AudioFormat format;


private DatagramSocket datagramSocket(){
    try {
        return new DatagramSocket();
    } catch (SocketException ex) {
        return null;
    }
}

private void startMic() {
    try {
        format = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, 8000.0F, 16, 2, 4, 8000.0F, true);
        DataLine.Info info = new DataLine.Info(TargetDataLine.class, format);
        mic = (TargetDataLine) AudioSystem.getLine(info);
        mic.open(format);
        mic.start();
        buffer = new byte[1024];
    } catch (LineUnavailableException ex) {
        Logger.getLogger(AudioSender.class.getName()).log(Level.SEVERE, null, ex);
    }
}

private Player createPlayer() {
    try {
        return Manager.createRealizedPlayer(ml);
    } catch (IOException ex) {
        return null;
    } catch (NoPlayerException ex) {
        return null;
    } catch (CannotRealizeException ex) {
        return null;
    }
}

private void send() {
    try {
        mic.read(buffer, 0, 1024);
        DatagramPacket packet = 
            new DatagramPacket(
                buffer, buffer.length, InetAddress.getByName(Util.getRemoteIP()), 91);
        socket.send(packet);
    } catch (IOException ex) {
        Logger.getLogger(AudioSender.class.getName()).log(Level.SEVERE, null, ex);
    }
}

@Override
public void run() {
    player = createPlayer();
    player.start();
    socket = datagramSocket();
    transmitting = true;
    startMic();
    while (transmitting) {
        send();
    }  
}

public static void main(String[] args) {
    AudioSender as = new AudioSender();
    as.start();
}

}

当我运行的接收器类，仅发生的事情，就是我听到从发送方类这个球员。
而我似乎看到TargetDataLine的和播放器之间的连接。
基本上，我需要的声音播放形式，并以某种方式将其转换为字节[]，所以我可以送它作为数据报。
有任何想法吗？一切都是可以接受的，只要它的工作原理：）

And only thing that happens when I run the receiver class, is me hearing this Player from the sender class. And I cant seem to see the connection between TargetDataLine and Player. Basically, I need to get the sound form player, and somehow convert it to bytes[], therefore I can sent it as datagram. Any ideas? Everything is acceptable, as long as it works :)

推荐答案

您不要在这里Player类，你想要什么使用类的 javax.sound.sampled中。至于我可以告诉播放器是播放声音，不能访问其内容。

You don't what the Player class here, you want to use the classes in javax.sound.sampled. As far as I can tell Player is for playing a sound, not accessing its contents.

我没有测试过这一点，但尝试使用.read的TargetDataLine的要创建以填补一个缓冲区，然后发送缓冲区到其他主机。

I have not tested this, but try using .read on the TargetDataLine you are creating to fill a buffer, and then sending the buffer to the other host.

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