删除多行注释 [英] Remove multi-line comments

问题描述

我如何删除所有的意见，如果他们开始与/ *带*号结束/
我曾尝试以下。它的工作原理一行注释。

How do I remove all comments if they start with /* and end with */ I have tried the following. It works for one line comment.

sed '/\/\*/d' 

但它不会删除多行注释。例如用于第二和第三线不会被删除。

But it does not remove multiline comments. for e.g. the second and third lines are not removed.

/*!50500 PARTITION BY RANGE (TO_SECONDS(date_time ))
 PARTITION 20120102parti VALUES LESS THAN (63492681600),
(PARTITION 20120101parti VALUES LESS THAN (63492595200) */ ;

在上面的例子中，我需要的保留最后。注释结束符号后

In the above example, I need to retain the last ; after the closing comment sign.

推荐答案

如果这是一个C文件，那么你必须使用C preprocessor这与其他工具的组合暂时禁用特定preprocessor功能像扩大＃定义或＃包括所有其他方法将在边缘的情况下失败。这将为所有情况：

If this is in a C file then you MUST use a C preprocessor for this in combination with other tools to temporarily disable specific preprocessor functionality like expanding #defines or #includes, all other approaches will fail in edge cases. This will work for all cases:

[ $# -eq 2 ] && arg="$1" || arg=""
eval file="\$$#"
sed 's/a/aA/g;s/__/aB/g;s/#/aC/g' "$file" |
          gcc -P -E $arg - |
          sed 's/aC/#/g;s/aB/__/g;s/aA/a/g'

把它放在一个shell脚本，并与你想要解析的文件的名字称呼它，用标志像-ansipfixed可选$ P $指定C标准提出申请。

Put it in a shell script and call it with the name of the file you want parsed, optionally prefixed by a flag like "-ansi" to specify the C standard to apply.

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