消除重复线路，并保持最后一个 [英] Eliminate duplicate lines and keep the last one

问题描述

我有一个看起来像这样的文件：

I have a file that looks like this:

2011-03-21 name001 line1
2011-03-21 name002 line2
2011-03-21 name003 line3
2011-03-22 name002 line4
2011-03-22 name001 line5

对于每个名字，我只希望它的最后一次亮相。所以，我希望得到的结果是：

for each name, I only want its last appearance. So, I expect the result to be:

2011-03-21 name003 line3
2011-03-22 name002 line4
2011-03-22 name001 line5

能有人给我使用bash的解决方案/ AWK / SED？

Could someone give me a solution with bash/awk/sed?

推荐答案

这code uniq的获取由行第二场但从文件或文本的结尾（就像你的结果为例）

This code get uniq lines by second field but from the end of file or text (like in your result example)

tac temp.txt | sort -k2,2 -r -u

这篇关于消除重复线路，并保持最后一个的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！