打印字段'N'到行尾 [英] Print Field 'N' to End of Line

问题描述

我想有一个问题，我在awk的帮助或方向。

I would like to have help or direction on a problem I have in awk.

我有超过5场制表符分隔的文件。我想输出不计首5个字段的字段。

I have a tab-delimited file with more than 5 fields. I want to output the fields excluding the first 5 fields.

你能告诉如何写awk脚本来完成这项任务？

Could you please tell how to write an awk script to accomplish this task?

最佳，
jianfeng.mao

Best, jianfeng.mao

请注意以下几点那种评论：

Do Note the following kind comment:

有在我的文件很多领域。不同的线路具有不同数量的域。每行中的字段的数目是不标准。

There are many fields in my files. Different lines have a different number of fields. The number of fields per line is not standard.

推荐答案

我同意matchew的建议，使用削减：这是这个工作的工具。但是，如果这仅仅是要成为一个更大的 AWK 脚本的一部分，这里是如何做到这一点：

I agree with matchew's suggestion to use cut: it's the right tool for this job. But if this is just going to become a part of a larger awk script, here's how to do it:

awk -F "\t" '{ for (i=6; i<=NF; ++i) $(i-5) = $i; NF = NF-5; print; }

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