用awk删除空白 [英] Using Awk to remove whitespace

问题描述

我在形式的文件：

Firstname LastName; 123-4567; Job Title
    Firstname LastName;   123-4567;      Job Title
Firstname LastName;      123-4567; Job Title
...

我想使用awk来解析该文件由成makedbm的读取的形式（以使自定义NIS映射）。字段分隔符是一个分号。我需要能够从每个字段在每一行中删除所有前导空格，但留下的空间在名称字段和标题字段。谢谢你。

I am trying to use awk to parse the file into a form readable by makedbm (to make a custom NIS map). Field separator is a semicolon. I need to be able to remove all leading whitespace from each field on each line, but leave the spaces in the name field and the title field. Thanks.

推荐答案

如果你想删除的 来自各个领域的前导空格 并保持 中的姓名和职位字段之间的空间 ，然后你可以做这样的事情 -

If you wish to remove leading space from all fields and keep the space in between the Names and Job title fields then you can do something like this -

awk -F";" -v OFS=";" '{for (i=1;i<=NF;i++) gsub (/^ */,"",$i);print}' INPUT_FILE

测试：

[jaypal:~/Temp] cat file
Firstname LastName; 123-4567; Job Title
    Firstname LastName;   123-4567;      Job Title
Firstname LastName;      123-4567; Job Title

[jaypal:~/Temp] awk -F";" -v OFS=";" '{for (i=1;i<=NF;i++) gsub (/^ */,"",$i);print}' file
Firstname LastName;123-4567;Job Title
Firstname LastName;123-4567;Job Title
Firstname LastName;123-4567;Job Title

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