从文件从另一个多发线替换多行 [英] Replace multiple lines from a file with mutiple lines from another

问题描述

我可以在几个命令，搜索和文件替换多个行？

Can I, in few commands, search and replace multiple lines in a file?

我试图以独特的故障切换块从 dhcp_secondary 替换从 dhcp_primary 3故障块，内 dhcp_primary 。

I'm trying to replace the 3 failover blocks from dhcp_primary by the unique failover block from dhcp_secondary, within dhcp_primary.

我的目标是到dhcpd.conf里从主DHCP这里复制到辅助（信息的 http://www.madboa.com/geek/dhcp-failover/ ）。故障转移工作只有配置是相同的，当然，除了故障转移块;正如你所看到的是网站的例子。
所以我想复制这个文件，但是从二级保留故障转移信息。

My goal is to copy the dhcpd.conf from a primary dhcp to the secondary (more information here: http://www.madboa.com/geek/dhcp-failover/). The failover work only if the configuration are identical, except the failover block of course; as you can see is the website's example. So I want to copy this file, but keep the failover information from the secondary.

示例 dhcp_primary ：

// some lines above
failover peer "A" {
...
}
failover peer "B" {
...
}
failover peer "C" {
...
}
// some lines below

示例 dhcp_secondary ：

// some different lines above
failover peer "D" {
...
}
// some different lines below

预期的输出必须是：

The expected output have to be:

// some lines above
failover peer "D" {
...
}
// some lines below

我已经可以提取故障切换块：

I already can extract the failover blocks :

awk '/^failover/,/^}$/' dhcp_a

awk '/^failover/,/^}$/' dhcp_b

但我不知道该怎么继续。

But I don't know how to continue.

先谢谢了。

编辑：我的目标更多的细节。

more details for my goal.

推荐答案

您可以试试：

awk -f a.awk dhcp_b dhcp_a

其中， a.awk 是：

/^failover/,/^}$/{
    if (NR==FNR) {
        blk=blk $0 RS
        next
    }
    if (++i==1) {
        printf "%s",blk
    }
    next
}
NR!=FNR{  print }

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