庆典：开始在后台的多个链接命令 [英] bash: start multiple chained commands in background

问题描述

我想在paralel运行某些命令，在后台，使用bash。这里就是我想要做的：

I'm trying to run some commands in paralel, in background, using bash. Here's what I'm trying to do:

forloop {
  //this part is actually written in perl
  //call command sequence
  print `touch .file1.lock; cp bigfile1 /destination; rm .file1.lock;`;
}

反引号（``）之间的部分产生一个新的外壳，相继执行的命令。问题是，已执行的最后一个命令后，才控制到原来的程序返回。我想执行的背景下，整个声明（我不期待任何输出/返回值），我想在循环继续运行。

The part between backticks (``) spawns a new shell and executes the commands in succession. The thing is, control to the original program returns only after the last command has been executed. I would like to execute the whole statement in background (I'm not expecting any output/return values) and I would like the loop to continue running.

调用程序（即具有循环中的一个）不会结束，直到所有的衍生弹完成。

The calling program (the one that has the loop) would not end until all the spawned shells finish.

我可以使用线程在Perl产卵不同的线程调用其中不同的炮弹，但似乎矫枉过正...

I could use threads in perl to spawn different threads which call different shells, but it seems an overkill...

我可以启动一个shell，给它一组命令，告诉它去后台？

Can I start a shell, give it a set of commands and tell it to go to the background?

推荐答案

我没有关于

print `(touch .file1.lock; cp bigfile1 /destination; rm .file1.lock;) &`;

括号意味着执行在子shell，但不应该伤害。

The parentheses mean execute in a subshell but that shouldn't hurt.

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