有效地检查几个命令的Bash的退出状态 [英] Checking Bash exit status of several commands efficiently

问题描述

有什么类似pipefail多个命令，就像一个'尝试'语句，但庆典之内。我愿做这样的事情：

Is there something similar to pipefail for multiple commands, like a 'try' statement but within bash. I would like to do something like this:

echo "trying stuff"
try {
    command1
    command2
    command3
}

和在任何时候，如果有命令失败，辍学和回声出命令的错误。我不希望有做这样的事情：

And at any point, if any command fails, drop out and echo out the error of that command. I don't want to have to do something like:

command1
if [ $? -ne 0 ]; then
    echo "command1 borked it"
fi

command2
if [ $? -ne 0 ]; then
    echo "command2 borked it"
fi

等等......之类的东西：

And so on... or anything like:

pipefail -o
command1 "arg1" "arg2" | command2 "arg1" "arg2" | command3

由于每个命令我相信（纠正我，如果我错了）的争论会互相干扰。这两种方法看似可怕的啰嗦和讨厌我，所以我在这里呼吁一个更有效的方法。

Because the arguments of each command I believe (correct me if I'm wrong) will interfere with each other. These two methods seem horribly long-winded and nasty to me so I'm here appealing for a more efficient method.

推荐答案

您可以编写一个启动和测试命令你的函数。假设命令1 和命令2 是已设置命令环境变量。

You can write a function that launches and tests the command for you. Assume command1 and command2 are environment variables that have been set to a command.

function mytest {
    "$@"
    local status=$?
    if [ $status -ne 0 ]; then
        echo "error with $1" >&2
    fi
    return $status
}

mytest $command1
mytest $command2

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