＆QUOT;找不到命令＆QUOT;试图在bash整数平等时， [英] "Command not found" when attempting integer equality in bash

问题描述

好吧，这可能会是超明显，任何人花了更多的时间使用bash，比我有。

Ok, this is probably going to be ultra obvious to anyone that has spent more time with bash than I have.

我试图运行此code：

I'm trying to run this code:

#!/bin/bash

if ["1" -eq "2"] 
then
    echo "True"
else
    echo "False"
fi

但是当我执行这个文件，它发回

but when I execute the file, it sends back

./test.sh: line 3: 1: command not found
False

有一定有什么重大的我失踪。我见过的人使用分号括号后，这似乎没有任何区别...：•

There must be something major I'm missing. I've seen people use a semicolon after the brackets, this doesn't seem to make any difference... :S

推荐答案

是的EQ仅用于算术comparaisons。

yep eq is used only for arithmetic comparaisons.

对于字符串比较，你必须使用 =

for string comparison you have to use =

#!/bin/bash

if [ "1" = "2" ] 
then
    echo "True"
else
    echo "False"
fi

再加上你需要周围的括号一些空间。

plus you need some space around the brackets.

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