如何列出在bash脚本中声明的变量？ [英] How to list variables declared in script in bash?

问题描述

在我的bash脚本，还有很多变数，我必须做出什么来拯救他们到文件。
我的问题是如何列出我的脚本声明的所有变量和获取列表是这样的：

  VARIABLE1 = ABC
变量2 =高清
VARIABLE3 = GHI
 

解决方案

设置将输出变量，遗憾的是它也将输出功能定义也是如此。

幸运的是POSIX模式只能输出变量：

 （设置-o POSIX;集）|减
 

管道到少，或重定向到您想要的选项。

因此​​，要在短短的剧本获得声明的变量：

 （设置-o POSIX;集）GT; /tmp/variables.before
源脚本
（设定-o POSIX;集）GT; /tmp/variables.after
差异/tmp/variables.before /tmp/variables.after
RM /tmp/variables.before /tmp/variables.after
 

（或至少基于:-)东西）

In my script in bash, there are lot of variables, and I have to make something to save them to file. My question is how to list all variables declared in my script and get list like this:

VARIABLE1=abc
VARIABLE2=def
VARIABLE3=ghi

解决方案

set will output the variables, unfortunately it will also output the functions defines as well.

Luckily POSIX mode only outputs the variables:

( set -o posix ; set ) | less

Piping to less, or redirect to where you want the options.

So to get the variables declared in just the script:

( set -o posix ; set ) >/tmp/variables.before
source script
( set -o posix ; set ) >/tmp/variables.after
diff /tmp/variables.before /tmp/variables.after
rm /tmp/variables.before /tmp/variables.after

(Or at least something based on that :-) )

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