时间命令自定义格式 [英] Custom format for time command

问题描述

我想使用时间在 bash脚本以计算脚本的运行时间和写入日志文件的命令。我只需要在实时，而不是用户和sys。另外还需要在一个体面的格式。例如00：00：00：00（不喜欢标准输出）。我AP preciate任何建议。

I'd like to use the time command in a bash script to calculate the elapsed time of the script and write that to a log file. I only need the real time, not the user and sys. Also need it in a decent format. e.g 00:00:00:00 (not like the standard output). I appreciate any advice.

本来预期格式为 00：00：00.0000 （毫秒）[时间]：[分钟]：[秒] [毫秒]

The expected format supposed to be 00:00:00.0000 (milliseconds) [hours]:[minutes]:[seconds].[milliseconds]

我已经3个脚本。我看到了一个这样的例子：

I've already 3 scripts. I saw an example like this:

{ time { # section code goes here } } 2> timing.log

不过，我只需要在实时性，而不是用户和sys。另外还需要在一个体面的格式。例如 00：00：00：00 （不喜欢标准输出）

在换句话说，我想知道如何把时间输出到工艺的东西更容易。

In other words, I'd like to know how to turn the time output into something easier to process.

推荐答案

您可以使用日期命令前，完成工作后能得到当前的时间要定时并计算这样的区别是：

You could use the date command to get the current time before and after performing the work to be timed and calculate the difference like this:

#!/bin/bash

# Get time as a UNIX timestamp (seconds elapsed since Jan 1, 1970 0:00 UTC)
T="$(date +%s)"

# Do some work here
sleep 2

T="$(($(date +%s)-T))"
echo "Time in seconds: ${T}"

printf "Pretty format: %02d:%02d:%02d:%02d\n" "$((T/86400))" "$((T/3600%24))" "$((T/60%60))" "$((T%60))""

注意：
$（（...））可用于基本的算术中的庆典的＆ndash的;注意：不要把空格减去之前的 - ，因为这可能会间preTED作为命令行选项

Notes: $((...)) can be used for basic arithmetic in bash – caution: do not put spaces before a minus - as this might be interpreted as a command-line option.

另请参阅： http://tldp.org/LDP/abs/html/arithexp.html

的编辑：的结果
此外，你可能想看看 SED 搜索并从生成的输出中提取子的时间

的编辑：的

例与毫秒时间（实际上纳秒，但截断至毫秒这里）。你的日期的版本有支持％N 格式和庆典应该支持大量涌现。

Example for timing with milliseconds (actually nanoseconds but truncated to milliseconds here). Your version of date has to support the %N format and bash should support large numbers.

# UNIX timestamp concatenated with nanoseconds
T="$(date +%s%N)"

# Do some work here
sleep 2

# Time interval in nanoseconds
T="$(($(date +%s%N)-T))"
# Seconds
S="$((T/1000000000))"
# Milliseconds
M="$((T/1000000))"

echo "Time in nanoseconds: ${T}"
printf "Pretty format: %02d:%02d:%02d:%02d.%03d\n" "$((S/86400))" "$((S/3600%24))" "$((S/60%60))" "$((S%60))" "${M}"

免责声明：结果
我原来的版本说

DISCLAIMER:
My original version said

M="$((T%1000000000/1000000))"

但被剪辑掉，因为它显然没有对某些人的工作，而新版本的报道一样。因为我认为你必须使用的唯一剩下的，但被多数票否决我不同意这一点。结果
选择任何适合你。

but this was edited out because it apparently did not work for some people whereas the new version reportedly did. I did not approve of this because I think that you have to use the remainder only but was outvoted.
Choose whatever fits you.

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