我如何使用IF语句时拆分为多行的bash命令? [英] How can I split a Bash command over multiple lines when using an IF statement?
本文介绍了我如何使用IF语句时拆分为多行的bash命令?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何能比我在猛砸,当命令是如果
语句的一部分?
How can I split a command over multiple lines in Bash, when the command is part of an if
statement?
虽然这个作品:
if ! fab --fabfile=.deploy/fabfile.py --forward-agent --disable-known-hosts deploy:$target; then
rc=1
fi
这是行不通的:
# does not work:
if ! fab --fabfile=.deploy/fabfile.py \
--forward-agent \
--disable-known-hosts deploy:$target; then
rc=1
fi
而不是整个命令执行的,我得到:
Instead of the whole command executing, I get:
./script.sh: line 73: --forward-agent: command not found
更重要的是,什么是从我的Bash的理解缺失,这将有助于我了解这一点,类似问题在未来?
More importantly, what is missing from my understanding of Bash that will help me understand this and similar issues in the future?
推荐答案
您确定你没有这些反斜杠后的任何空白?你的榜样正常工作对我来说:
You sure you don't have any whitespace after those backslashes? Your example works fine for me:
$ cat test.sh
if ! fab --fabfile=.deploy/fabfile.py \
--forward-agent \
--disable-known-hosts deploy:$target; then
echo failed
else
echo succeeded
fi
$ alias fab=true
$ . ./test.sh
succeeded
$ alias fab=false
$ . ./test.sh
failed
这篇关于我如何使用IF语句时拆分为多行的bash命令?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文