将输出重定向到一个bash数组 [英] Redirect output to a bash array

问题描述

我有一个包含字符串的文件

I have a file containing the string

ipAddress=10.78.90.137;10.78.90.149

我想打这两个IP地址在bash阵列。为了达到这个我试过如下：

I'd like to place these two IP addresses in a bash array. To achieve that I tried the following:

n=$(grep -i ipaddress /opt/ipfile |  cut -d'=' -f2 | tr ';' ' ')

这导致在正常的提取值，但由于某些原因所述阵列的大小被返回为1，我注意到，这两个值被确定为在阵列中的第一个元素。这就是

This results in extracting the values alright but for some reason the size of the array is returned as 1 and I notice that both the values are identified as the first element in the array. That is

echo ${n[0]}

返回

10.78.90.137 10.78.90.149

我该如何解决这个问题？

How do I fix this?

感谢您的帮助！

推荐答案

你真的需要一个数组

庆典

$ ipAddress="10.78.90.137;10.78.90.149"
$ IFS=";"
$ set -- $ipAddress
$ echo $1
10.78.90.137
$ echo $2
10.78.90.149
$ unset IFS
$ echo $@ #this is "array"

如果你想放入数组

$ a=( $@ )
$ echo ${a[0]}
10.78.90.137
$ echo ${a[1]}
10.78.90.149

@OP，关于你的方法：设置为IFS空间

@OP, regarding your method: set your IFS to a space

$ IFS=" "
$ n=( $(grep -i ipaddress file |  cut -d'=' -f2 | tr ';' ' ' | sed 's/"//g' ) )
$ echo ${n[1]}
10.78.90.149
$ echo ${n[0]}
10.78.90.137
$ unset IFS

此外，也没有必要使用这样的工具。你可以只用awk，或者干脆使用bash shell

Also, there is no need to use so many tools. you can just use awk, or simply the bash shell

#!/bin/bash
declare -a arr
while IFS="=" read -r caption addresses
do
 case "$caption" in 
    ipAddress*)
        addresses=${addresses//[\"]/}
        arr=( ${arr[@]} ${addresses//;/ } )
 esac
done < "file"
echo ${arr[@]}

输出

$ more file
foo
bar
ipAddress="10.78.91.138;10.78.90.150;10.77.1.101"
foo1
ipAddress="10.78.90.137;10.78.90.149"
bar1

$./shell.sh
10.78.91.138 10.78.90.150 10.77.1.101 10.78.90.137 10.78.90.149

gawk的

$ n=( $(gawk -F"=" '/ipAddress/{gsub(/\"/,"",$2);gsub(/;/," ",$2) ;printf $2" "}' file) )
$ echo ${n[@]}
10.78.91.138 10.78.90.150 10.77.1.101 10.78.90.137 10.78.90.149

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