回合一击数除以 [英] Round a divided number in Bash

问题描述

我将如何圆其结果，从一分为二的数字，例如。

How would I round the result from two divided numbers, e.g.

3/2

当我这样做

testOne=$((3/2))

$ testOne含1时，它应该已经四舍五入为2为从3/2 = 1.5的答案

$testOne contains "1" when it should have rounded up to "2" as the answer from 3/2=1.5

推荐答案

庆典不会给你的3/2正确的结果，因为它没有做浮动PT数学。你可以像使用AWK工具

bash will not give you correct result of 3/2 since it doesn't do floating pt maths. you can use tools like awk

$ awk  'BEGIN { rounded = sprintf("%.0f", 3/2); print rounded }'
2

或BC

$ printf "%.0f" $(echo "scale=2;3/2" | bc)
2

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