Grepping一个巨大的文件（80GB）的方式来加快步伐？ [英] Grepping a huge file (80GB) any way to speed it up?

问题描述

 grep -i -A 5 -B 5 'db_pd.Clients'  eightygigsfile.sql

这已经运行了一个小时它，否则不超载一个相当强大的Linux服务器。
任何其他与grep？关于我的语法可以改善，任何东西（的egrep，fgrep一样好？）

This has been running for an hour on a fairly powerful linux server which is otherwise not overloaded. Any alternative to grep? Anything about my syntax that can be improved, (egrep,fgrep better?)

的文件实际上是在其与安装共享到另一台服务器，但实际磁盘空间的目录是本地所以，不应该有什么区别？

The file is actually in a directory which is shared with a mount to another server but the actual diskspace is local so that shouldn't make any difference?

grep的被抓高达93％的CPU

the grep is grabbing up to 93% CPU

推荐答案

下面是几个选项：

1）preFIX你的grep命令使用C语言环境，而不是UTF-8。

1) Prefix your grep command with LC_ALL=C to use the C locale instead of UTF-8.

2）使用 fgrep一样，因为你正在寻找一个固定的字符串，而不是常规的前pression。

2) Use fgrep because you're searching for a fixed string, not a regular expression.

3）删除 -i 选项，如果你不需要它。

3) Remove the -i option, if you don't need it.

所以你的命令就变成了：

So your command becomes:

LC_ALL=C fgrep -A 5 -B 5 'db_pd.Clients' eightygigsfile.sql

这也将是更快，如果你复制你的文件到RAM盘。

It will also be faster if you copy your file to RAM disk.

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