shell脚本：对任何错误死亡 [英] Shell scripting: die on any error

问题描述

假设一个shell脚本（/ bin / sh的或/斌/ bash）的包含多个命令。我如何才能干净地使脚本终止，如果任何命令都有一个失败退出状态？很明显，可以使用if块和/或回调，但有一个更清洁，更简洁的方法吗？使用和放大器;＆安培;是不是一个真正的选择要么，因为这些命令可能会很长，或者脚本可以像循环和条件不平凡的事情。

Suppose a shell script (/bin/sh or /bin/bash) contained several commands. How can I cleanly make the script terminate if any of the commands has a failing exit status? Obviously, one can use if blocks and/or callbacks, but is there a cleaner, more concise way? Using && is not really an option either, because the commands can be long, or the script could have non-trivial things like loops and conditionals.

推荐答案

使用标准的 SH 和庆典，你可以

set -e

它将

$ help set
...
        -e  Exit immediately if a command exits with a non-zero status.

它也可以（从我可以收集）与的zsh 。它也应该适用于任何Bourne shell的后裔。

It also works (from what I could gather) with zsh. It also should work for any Bourne shell descendant.

使用 CSH / 的tcsh ，你必须用＃启动你的脚本！/斌/ CSH -e

With csh/tcsh, you have to launch your script with #!/bin/csh -e

这篇关于shell脚本：对任何错误死亡的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！