在bash shell脚本识别接收到的信号名称 [英] Identifying received signal name in bash shell script

问题描述

当接收到信号，我可以使用陷阱执行某些命令。如果指定的任何信号的接收，显示的hello world。例如：

When a signal is received, I can execute some commands using trap . If any of the signals specified is received, the hello world' is displayed. Example:

trap 'echo hello world' 1 2

但我怎么能打印/识别接收到的信号的名字吗？

But How can I print/identify the received signal name ?

推荐答案

（如果你只有一个信号的数量和所需的名称，杀-l $ SIGNAL_NUM 打印信号的名称，那么就可以避免使用信号名称，而不是在你的电话号码，以陷阱如下）

(If you only have the number of a signal and want the name, kill -l $SIGNAL_NUM prints the name of a signal; you can avoid that by using the signal names instead of numbers in your call to trap as below.)

这个答案说，只有这样，才能确定哪些信号时，在bash困是写为每个不同的信号的单独包装要陷阱。它提供了一个包装函数来为你做它：

This answer says that the only way to identify which signal you trapped in bash is to write a separate wrapper for each different signal you want to trap. It provides a wrapper function to do it for you:

code：

#!/bin/bash

trap_with_arg() {
    func="$1" ; shift
    for sig ; do
        trap "$func $sig" "$sig"
    done
}

func_trap() {
    echo Trapped: $1
}

trap_with_arg func_trap INT TERM EXIT

read # Wait so the script doesn't exit.

如果我运行的，那么我就可以发送信号的过程中，我得到这样

If I run that, then I can send signals to the process and I get output like

Trapped: INT
Trapped: TERM
Trapped: EXIT

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