如何从另一个shell发送信号到bash脚本 [英] How to send signal to a bash script from another shell
问题描述
我开始下面的脚本,我在bash shell中运行(假设抽壳)的前景,并从另一个shell(shell2)我送杀-SIGUSR1的pidof(scriptA)。什么都没发生。我究竟做错了什么?我试过其他信号(SIGQUIT等),但结果是一样的。
test_trap.sh
功能iAmDone {回声困信号;退出0}
陷阱iAmDone SIGUSR1
回声运行......
尾-f的/ dev / null的#什么也不做
在抽壳
./ test_trap.sh
在shell2
杀-SIGUSR1的ps aux | grep的[T] est_trap | AWK'{打印$ 2}'
该陷阱直到尾完成执行。但尾巴永远不会完成。尝试:
尾-f的/ dev / null的&安培;
等待
陷阱将执行,而无需等待尾完成,但如果你退出尾巴会留下运行。所以,你可能会想一个 $杀!
中的陷阱。
I start the following script which I run in a bash shell(let's say shell1) in foreground and from another shell(shell2) I send the kill -SIGUSR1 pidof(scriptA). Nothing happens. What am I doing wrong ? I tried other signals(SIGQUIT etc) but the result is same.
test_trap.sh
function iAmDone { echo "Trapped Signal"; exit 0 }
trap iAmDone SIGUSR1
echo "Running... "
tail -f /dev/null # Do nothing
In shell1
./test_trap.sh
In shell2
kill -SIGUSR1 ps aux | grep [t]est_trap | awk '{print $2}'
The trap is not executed until tail finishes. But tail never finishes. Try:
tail -f /dev/null &
wait
The trap will execute without waiting for tail to complete, but if you exit the tail will be left running. So you'll probably want a kill $!
in the trap.
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