从另一个脚本运行shell脚本 [英] running a shell script from another script

问题描述

我在UNIX脚本，看起来像这样：

I have a script in unix that looks like this:

#!/bin/bash

gcc  -osign sign.c

./sign < /usr/share/dict/words | sort | squash > out

每当我尝试运行此脚本它给了我一个错误说，壁球不是一个有效的命令。壁球是存储在同一目录这个脚本的shell脚本，看起来像这样：

Whenever I try to run this script it gives me an error saying that squash is not a valid command. squash is a shell script stored in the same directory as this script and looks like this:

#!/bin/bash
awk -f squash.awk

我有正确执行权限设置，但由于某种原因，它不运行。有没有别的东西我必须做的，使它能够运行像显示？我是相当新的脚本所以任何帮助将不胜AP preciated！

I have execute permissions set correctly but for some reason it doesn't run. Is there something else I have to do to make it able to run like shown? I am rather new to scripting so any help would be greatly appreciated!

推荐答案

正如上文@比芬的评论，除非。是在 $ PATH 变量，你需要指定 ./壁球你需要指定同样的原因 ./签署。

As mentioned in @Biffen's comment, unless . is in your $PATH variable, you need to specify ./squash for the same reason you need to specify ./sign.

在命令行上解析裸字，庆典将检查 $ PATH中列出的所有目录来看看说字是一个可执行文件的生活中的任何人。除非。是 $ PATH 时，bash不会找到壁球。

When parsing a bare word on the command line, bash checks all the directories listed in $PATH to see if said word is an executable file living inside any of them. Unless . is in $PATH, bash won't find squash.

要避免这个问题，你可以告诉bash不能去给予的bash它的完整路径寻找壁球，即 ./壁球。

To avoid this problem, you can tell bash not to go looking for squash by giving bash the complete path to it, namely ./squash.

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