在bash的参数太多错误 [英] Too many arguments error in bash

问题描述

我写一个脚本，删除目录中的所有文件的做法。我使用引号我的变量，但我仍然收到以下错误：

I am writing a script to delete all files in a directory for practice. I am using quotes around my variables, and yet I am still getting the following error:

/usr/local/bin/deleteall: line 6: [: too many arguments
/usr/local/bin/deleteall: line 11: [: too many arguments 

下面是我的code：

#!/bin/bash
#Deletes all files in the current directory

read -p "You are about to delete all files in $(pwd). Are you sure you want to do this? y/n" yn
echo $yn
if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then
        for i in `ls`; do
                rm $i
        done
        exit;
elif [ [ "$yn" = "n" ] -o [ "$yn" = "N" ] ] ; then
        exit;
else
        read -p "Please enter y (yes) or n (no)"
        exit;
fi

这是整个输出：

You are about to delete all files in <my dir>. Are you sure you want to do this? y/nn
n
/usr/local/bin/deleteall: line 6: [: too many arguments
/usr/local/bin/deleteall: line 11: [: too many arguments
Please enter y (yes) or n (no)n

我在做什么错了？

What am I doing wrong?

推荐答案

此行​​似乎是问题：

if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then

您可以用替换此：

if [[ "$yn" == [yY] ]]; then

PS：做同样的，你检查线路 N或N

PS: Do same for the line where you check n or N.

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