grep在if处有太多参数 [英] Too much arguments with grep at if

问题描述

我试图在文件中寻找$allowtunnel字符串.

I was trying to look for $allowtunnel string at my file.

基于:如何测试是否Bash shell文件中是否存在字符串?

所以现在我在脚本中有以下内容:

So now I've the following at my script:

allowtunnel="PermitTunnel"
if [ grep -Fxq $allowtunnel /etc/ssh/sshd_config ]; then

因为在执行时它说参数太多"，所以我一直在寻找并发现:

Since at execution time it says "too much arguments", I was looking and found this:

Bash脚本-参数过多

所以我将其更改为:

if [[ grep -Fxq $allowtunnel /etc/ssh/sshd_config ]]; then

但是现在，它为我提供了下一个:

But now, It delivers me the next one:

./script_install.sh: línea 242: se esperaba un operador binario condicional
./script_install.sh: línea 242: error sintáctico cerca de `-Fxq`
./script_install.sh: línea 242: `    if [[ grep -Fxq $allowtunnel /etc/ssh/sshd_config ]]; then`

翻译为:

./script_install.sh: line 242: binary conditional operator was expected
./script_install.sh: line 242: syntax error near of `-Fxq`
./script_install.sh: line 242: `    if [[ grep -Fxq $allowtunnel /etc/ssh/sshd_config ]]; then`

据我所知，它不允许我使用第二个[]，因为它需要另一个运算符.那让我不知道该怎么办.

So as I understand, It doesn't let me use a second [] because it expects another operator. That leaves me without knowing what to do.

我也看到了这一点: bash中的参数过多错误，但是由于我不是在比较什么，而是在等待grep的结果，因此我可以从中得到任何有用的信息.

I've also seen this one: Too many arguments error in bash , but since I'm not comparing something but waiting for the result of grep I get anything useful from this one.

感谢阅读

推荐答案

由于grep返回退出状态(取决于是否找到记录)，因此可以编写if语句，如下所示:

Since grep returns an exit status depending if the record is found or not, you could write your if statement like:

if grep .....; then

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