grep多个bash参数 [英] Grep multiple bash parameters

问题描述

我遇到的问题是我无法egrep数量不确定的变量作为参数传递给bash脚本

我希望它执行以下操作：

给定随机数参数。即：

  ./ searchline.sh ABC 
  

对第一个做一个grep，然后用其他的方法处理结果：

  grepA* | egrep B | egrep C 
  

我试图做的是用egreps构建一个字符串：

  for j in$ {@：2}; 
做
 ADDITIONALSEARCH =$ ADDITIONALSEARCH | egrep $ j; 
完成
 
 grep$ 1*$ ADDITIONALSEARCH
  

但不知何故，这将无法正常工作，似乎bash不会将egrep字符串视为egrep。

你们有什么建议吗？

>

顺便说一句，作为一个附注，我无法创建任何辅助文件，所以我猜grep -f不在线。还要注意，传递给bash脚本的参数数量是可变的，所以我不能做egrep$ 2| egrep$ 3。

预先感谢。

费尔南多

bin / bash

if [[$＃-gt 0]];然后
TEMP =（grep-e\\ $ 1 \*）
for（（I = 2; I <= $＃; ++一世 ））;做
TEMP =（$ {TEMP [@]}|egrep-e\\ $$ {I} \）
完成
eval$ {TEMP [@]}
fi

运行它：

  bash script.sh ABC 
  

I'm writing a bash script which shall search in multiple files.

The problem I'm encountering is that I can't egrep an undetermined number of variables passed as parameters to the bash script

I want it to do the following:

Given a random number of parameters. i.e:

./searchline.sh A B C

Do a grep on the first one, and egrep the result with the rest:

grep "A" * | egrep B | egrep C

What I've tried to do is to build a string with the egreps:

for j in "${@:2}";
do
ADDITIONALSEARCH="$ADDITIONALSEARCH | egrep $j";
done

grep "$1" * "$ADDITIONALSEARCH"

But somehow that won't work, it seems like bash is not treating the "egrep" string as an egrep.

Do you guys have any advice?

By the way, as a side note, I'm not able to create any auxiliary file so grep -f is out of the line I guess. Also note, that the number of parameters passed to the bash script is variable, so I can't do egrep "$2" | egrep "$3".

Thanks in advance.

Fernando

解决方案

A safe eval could be a good solution

#!/bin/bash

if [[ $# -gt 0 ]]; then
    TEMP=("grep" "-e" "\"\$1\"" "*")
    for (( I = 2; I <= $#; ++I )); do
        TEMP=("${TEMP[@]}" "|" "egrep" "-e" "\"\$${I}\"")
    done
    eval "${TEMP[@]}"
fi

To run it:

bash script.sh A B C

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