算上在bash可执行文件的数量 [英] Count the number of executable files in bash

问题描述

我已经看到了很多关于这个问题的答案，但我并不想这样做，使用
找到。我写了这个东西，但不工作：

I have seen a lot of answers about this subject but I don't want to do this using find. I have written this but something not working:

function CountEx()
{
    count=0
    for file in `ls $1`
    do
        echo "file is $file"
        if [ -x $file ]
        then
            count=`expr $count + 1`
        fi
    done
    echo "The number of executable files in this dir is: $count"
}
while getopts x:d:c:h opt
do
    case $opt in
        x)CountEx $OPTARG;;
        d)CountDir $OPTARG;;
        c)Comp $OPTARG;;
        h)help;;
        *)echo "Please Use The -h Option to see help"
        break;;
    esac
done

我使用这个脚本如下所示：

I am using this script like the following:

yaser.sh -x './..../...../.....'

外壳运行它，然后它输出：
在这个目录可执行文件的数量是：0
当有此目录中的许多可执行文件。

The shell runs it and then it outputs: The number of executable files in this dir is: 0 when there is many executable files in this directory.

推荐答案

要算可执行文件的数量（如标题所说）

To count the number of executable (like the title says)

 count=0 
 for file in yourdir/*; do 
     if [ -x $file ]; then 
         count=$((count+1)); 
     fi; 
 done; 
 echo "total ${count}"

要算的文件夹，只需更改与 -d

To count folders, just change the -x test with -d

这篇关于算上在bash可执行文件的数量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！