如何创建子目录不存在递归使用bash？ [英] How to create nonexistent subdirectories recursively using Bash?

问题描述

我创建一个快速备份脚本，将倾倒一些数据库到一个不错的/整齐的目录结构，我意识到，我需要测试，以确保之前，我创建它们的目录是否存在。在code我的作品，但似乎有一个更好的方式来做到这一点。有什么建议？

  [-d$ BACKUP_DIR] || MKDIR$ BACKUP_DIR
[-d$ BACKUP_DIR / $客户端] || MKDIR$ BACKUP_DIR / $客户端
[-d$ BACKUP_DIR / $客户端/ $年] || MKDIR$ BACKUP_DIR / $客户端/ $年
[-d$ BACKUP_DIR / $客户端/年$ / $月] || MKDIR$ BACKUP_DIR / $客户端/年$ / $月
[-d$ BACKUP_DIR / $客户端/ $年/月$ / $日] || MKDIR$ BACKUP_DIR / $客户端/ $年/月$ / $日
 

解决方案

您可以使用 -p 参数，这是的记录为：

  

-p，--parents

  
  

没有错误，如果存在，使父目录需要

所以：

 的mkdir -p$ BACKUP_DIR / $客户端/ $年/月$ / $日
 

I am creating a quick backup script that will dump some databases into a nice/neat directory structure and I realized that I need to test to make sure that the directories exist before I create them. The code I have works, but it seems that there is a better way to do it. Any suggestions?

[ -d "$BACKUP_DIR" ] || mkdir "$BACKUP_DIR"
[ -d "$BACKUP_DIR/$client" ] || mkdir "$BACKUP_DIR/$client"
[ -d "$BACKUP_DIR/$client/$year" ] || mkdir "$BACKUP_DIR/$client/$year"
[ -d "$BACKUP_DIR/$client/$year/$month" ] || mkdir "$BACKUP_DIR/$client/$year/$month"
[ -d "$BACKUP_DIR/$client/$year/$month/$day" ] || mkdir "$BACKUP_DIR/$client/$year/$month/$day"

解决方案

You can use the -p parameter, which is documented as:

-p, --parents

no error if existing, make parent directories as needed

So:

mkdir -p "$BACKUP_DIR/$client/$year/$month/$day"

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