什么是执行中的Bash时间戳比较的最佳途径 [英] What is the Best Way to Perform Timestamp Comparison in Bash

问题描述

我有我试图从垃圾邮件我留着，所以我想打一个条件，如果警报已内发送，说最后一个小时的警报脚本，不发送另一个警报。现在我有一个检查条件的每一分钟，因为我需要在条件满足时迅速惊动但我并不需要得到每一个邮件，直到munite我得到控制的问题cron作业。什么是bash中进行比较的时间做到这一点的最佳方式？

I have an alert script that I am trying to keep from spamming me so I'd like to place a condition that if an alert has been sent within, say the last hour, to not send another alert. Now I have a cron job that checks the condition every minute because I need to be alerted quickly when the condition is met but I don't need to get the email every munite until I get the issue under control. What is the best way to compare time in bash to accomplish this?

推荐答案

目前最简单的是存储时间标记为空文件修改时间。 GNU 触摸和日期命令可以设置/获取这些时间和执行日期计算。 Bash有测试，以检查文件是否比小于（ -ot ）的另一个新的（ -nt ）或以上。

By far the easiest is to store time stamps as modification times of dummy files. GNU touch and date commands can set/get these times and perform date calculations. Bash has tests to check whether a file is newer than (-nt) or older than (-ot) another.

例如，只发送一个通知，如果最后通知是一个多小时前更多：

For example, to only send a notification if the last notification was more than an hour ago:

touch -d '-1 hour' limit
if [ limit -nt last_notification ]; then
    #send notification...
    touch last_notification
fi

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