如何从由cron运行的脚本运行GPG？ [英] How to run gpg from a script run by cron?

问题描述

我有了，看起来像一个部分的脚本：

I have a script that has a part that looks like that:

for file in `ls *.tar.gz`; do
  echo encrypting $file
  gpg --passphrase-file /home/$USER/.gnupg/backup-passphrase \
    --simple-sk-checksum -c  $file
done

有关，如果我手动运行该脚本某些原因，工作完全正常，所有文件都是加密的。如果我运行这个作为cron作业，回声$文件工作正常（我看加密＆LT;文件＆gt;在日志中），但文件不会被加密， GPG沉默失败，并没有标准输出/ stderr输出。

For some reason if I run this script manually, works perfectly fine and all files are encrypted. If I run this as cron job, echo $file works fine (I see "encrypting <file>" in the log), but the file doesn't get encrypted and gpg silent fails with no stdout/stderr output.

任何线索？

推荐答案

事实证明，答案是比我预想的更容易。有一个 - 批参数丢失，GPG试图从/ dev / tty的，不为cron作业存在阅读。要调试，我已经使用 - 出口通状态写入错误参数。但要使用我被退出状态2，呼应 $？如CD-人提出报道的启发。

It turns out that the answer was easier than I expected. There is a --batch parameter missing, gpg tries to read from /dev/tty that doesn't exist for cron jobs. To debug that I have used --exit-on-status-write-error param. But to use that I was inspired by exit status 2, reported by echoing $? as Cd-Man suggested.

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