使用bash脚本查找字符串的行号文件 [英] Using Bash Script to Find Line Number of String in File

问题描述

我如何使用bash脚本来查找行号的字符串出现？

How can I use a bash script to find the line number where a string occurs?

例如，如果一个文件看起来像这样，

For example if a file looked like this,

Hello I am Isaiah
This is a line of text.
This is another line of text.

和我跑了脚本查找字符串行这将输出数字2，因为这是第一次出现。

and I ran the script to look for the string "line" it would output the number 2, as it is the first occurance.

推荐答案

由于您的示例只打印字符串的第一次出现的行号，也许你正在寻找：

Given that your example only prints the line number of the first occurrence of the string, perhaps you are looking for:

awk '/line/{ print NR; exit }' input-file

如果你真的想所有的事件（例如，如果你的榜样的期望输出实际上是2 \\ N3 \\ n），省略了退出。

If you actually want all occurrences (eg, if the desired output of your example is actually "2\n3\n"), omit the exit.

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