shell脚本查找字符串的第n个出现位置并打印行号 [英] shell script to find the nth occurrence of a string and print the line number

问题描述

我有一个名为hello的文件，其中包含以下数据

I have a file named hello with the following data

onefish
onechicken
twofish
twochicken
threechicken
twocows

我想获取第二次出现chicken的行号.

I want to get the line number at which chicken is occurring for the second time.

在第4行中第二次出现chicken时，输出应为"4".

Output should be "4" as chicken occurs for the second time in 4th line.

推荐答案

您可以为此使用awk:

You can use awk for this:

awk '/chicken/{++n; if (n==2) { print NR; exit}}' file

4

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